Mary Coryell
Mary Coryell (maiden name unknown) was born around 1814 in New York. She married A. C. Coryell, and they had at least five children: Mary, born on September 3, 1835; Josephine, born around 1840; Lafayette, born around 1842; Lyman, born around 1845; and LeRoy, born around 1849. They lived in Catharine, New York, and her husband worked as a farmer. By 1850, they owned $4,000 of real estate. She died sometime after 1861.
3531
DATABASE CONTENT
(3531)Coryell, Mary1814
  • Conflict Side: Union
  • Role: Civilian
  • Rank in:
  • Rank out:
  • Rank highest:
  • Gender: Female
  • Race: White

Documents - Records: 1

  • (9606) [writer] ~ Mary Coryell to Mary C. Shibley and Oliver W. Shibley, 23 January 186X

People - Records: 4

  • (3531) Coryell, Mary is the [parent-in-law of] (3481) Shibley, Oliver W.
  • (3531) Coryell, Mary is the [parent of] (3482) Shibley, Mary C.
  • (3527) Coryell, Josephine is the [child of] (3531) Coryell, Mary
  • (3530) Coryell, Charles Henry is the [child of] (3531) Coryell, Mary

Places - Records: 3

  • (67) [birth] ~ New York
  • (2422) [residence in 1860] ~ Oswego, Kendall County, Illinois
  • (3760) [residence in 1870] ~ Bennezette, Butler County, Iowa

Show in Map

SOURCES

1850 United States Federal Census, available from Ancestry.com